document.write( "Question 623768: Hi, \r
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document.write( " I am reviewing to retake the SAT's and need help with the following problem.\r
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document.write( "If the perimeter of a rectangular property is 46 meters, and the area of the property is 76 meters squared, what is the length of each of the shorter sides?\r
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document.write( "Knowing the steps to take would be very helpful.
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document.write( "Thanks!! \n" );
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Algebra.Com's Answer #392300 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! P = 2L + 2W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"If the perimeter of a rectangular property is 46 meters\" ---> P = 46\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "46 = 2L + 2W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( "\n" ); document.write( "Area = Length * Width\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = LW\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"the area of the property is 76 meters squared\" ----> A = 76\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "76 = LW\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "W = 76/L\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------\r \n" ); document.write( "\n" ); document.write( "46 = 2L + 2W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "46 = 2L + 2(76/L)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll let you finish up. Let me know if you have any questions or if you still need help. Thanks. \n" ); document.write( " \n" ); document.write( " |