document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=623736>Question 623736</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve this ? A total of 150 tickets were sold for an annual concert to students and non students. Student tickets were $5 and non students were $8. If the total revenue for the concert was $930, then how many tickets of each were sold ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #392263 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=392263\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are two relationships described.  <P><BR>\n" );
document.write( "#1...total tickets which is made up of student tickets (s) and non student tickets (n) totals 150. Set up an equationL  s+n=150.  Solve one in terms of the other:  s=150-n.<P><BR>\n" );
document.write( "#2  Student tickets are $5 so the total revenue from student tickets is 5s (5 dollars times the number (s) of student tickets.)  Total revenue from non student tickets (n) is 8n.  The total revenue was $930 so 5s + 8n = 930.<P><BR>\n" );
document.write( "Substitute the s in terms of n (s=150-n) into that second equation (5s + 8n =930)<P><BR>\n" );
document.write( "5(150-n) + 8n = 930 --> 750 -5n + 8n = 930 ---> 3n = 180 ---> n=60.<p><BR>\n" );
document.write( "s=150-n = 150-60 = 90.<BR>\n" );
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