document.write( "Question 623704: The velocity v of an object t seconds after it has been dropped from a height above the surface of the earth is given by the equation v=32t feet per second, assuming no air resistance. If we assume that air resistance is proportional to the square of the velocity, then the velocity after t seconds is given by the following equation.
\n" ); document.write( "v=100((e^.64t-1)/(e^.64t+1))
\n" ); document.write( "In how many seconds will the velocity be 50 feet per second?
\n" ); document.write( "Getting the answer would be nice, but I would really appreciate an explanation as well. Thank you ! \n" ); document.write( "
Algebra.Com's Answer #392256 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
v=100((e^.64t-1)/(e^.64t+1))
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\n" ); document.write( "100((e^.64t-1)/(e^.64t+1)) = 50
\n" ); document.write( "((e^.64t-1)/(e^.64t+1)) = 0.5
\n" ); document.write( "e^.64t-1 = 0.5*(e^.64t + 1) = 0.5e^64t + 0.5
\n" ); document.write( "e^.64t - 0.5*e^.64t = 1.5
\n" ); document.write( "0.5*e^.64t = 1.5
\n" ); document.write( "e^.64t = 3
\n" ); document.write( "0.64t = ln(3)
\n" ); document.write( "t = ln(3)/0.64
\n" ); document.write( "t =~ 1.7166 seconds
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