document.write( "Question 623632: If $3,800 is invested in a savings account for which interest is compounded quarterly, and if the $3,800 turns into $4,300 in 2 years, what is the interest rate of the savings account?\r
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Algebra.Com's Answer #392188 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( " In General \"A+=+P%281%2Br%2Fn%29%5E%28nt%29\"
\n" ); document.write( "A = Accumulated Amount $4,300
\n" ); document.write( "P= principal = $3,800
\n" ); document.write( "r= annual rate = .
\n" ); document.write( "n= periods per year = 4
\n" ); document.write( "t= years = 2
\n" ); document.write( "\"A+=+P%281%2Br%2Fn%29%5E%28nt%29\"
\n" ); document.write( "\"4300%2F3800+=+%281%2Br%2F4%29%5E%284%2A2%29\"
\n" ); document.write( " log(43/38) =8 log(1 + r/4)
\n" ); document.write( " .0067 = log(1 + r/4)
\n" ); document.write( " 10^(.0067) = 1 + r/4 | Solve for r \n" ); document.write( "
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