document.write( "Question 623586: The sum of 3 consecutive integral numbers is 117. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #392182 by lenny460(1073)![]() ![]() You can put this solution on YOUR website! Let the three (3) consecutive integral numbers be:\r \n" ); document.write( "\n" ); document.write( "n\r \n" ); document.write( "\n" ); document.write( "n + 1\r \n" ); document.write( "\n" ); document.write( "n + 2\r \n" ); document.write( "\n" ); document.write( "Add the numbers together:\r \n" ); document.write( "\n" ); document.write( "n + n + 1 + n + 2\r \n" ); document.write( "\n" ); document.write( "Combine like terms:\r \n" ); document.write( "\n" ); document.write( "n + n + n = 3n\r \n" ); document.write( "\n" ); document.write( "1 + 2 = 3\r \n" ); document.write( "\n" ); document.write( "Therefore:\r \n" ); document.write( "\n" ); document.write( "3n + 3 = 117\r \n" ); document.write( "\n" ); document.write( "Subtract 3 from each side of the equation.\r \n" ); document.write( "\n" ); document.write( "3n + 3 - 3 = 117 - 3\r \n" ); document.write( "\n" ); document.write( "Combine like terms:\r \n" ); document.write( "\n" ); document.write( "3 - 3 = 0\r \n" ); document.write( "\n" ); document.write( "117 - 3 = 114\r \n" ); document.write( "\n" ); document.write( "3n = 114\r \n" ); document.write( "\n" ); document.write( "Divide each side by 3\r \n" ); document.write( "\n" ); document.write( "3n/3 = 114/3\r \n" ); document.write( "\n" ); document.write( "n = 38\r \n" ); document.write( "\n" ); document.write( "n + 1 = 38 + 1 = 39\r \n" ); document.write( "\n" ); document.write( "n + 2 = 38 + 2 = 40\r \n" ); document.write( "\n" ); document.write( "Check: 38 + 39 + 40 = 117\r \n" ); document.write( "\n" ); document.write( "The three (3) consecutive integral numbers are:\r \n" ); document.write( "\n" ); document.write( "38, 39 and 40.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "obuong3@aol.com \n" ); document.write( " |