document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=623547>Question 623547</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x^2=13x+56\r<BR>\n" );
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document.write( "3x^2-13x=56<BR>\n" );
document.write( "then <BR>\n" );
document.write( "x(3x-13)=56\r<BR>\n" );
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document.write( "x=56\r<BR>\n" );
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document.write( "3(56) -13. The result that i have is wrong; i do believe that i'm following the right process, but made a slight error, or maybe i missed a step. Your help is appreciated.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #392163 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=392163\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you're dealing with a quadratic equation so follow the rule for solving quadratic equations.<BR>\n" );
document.write( "your equation is:<BR>\n" );
document.write( "3x^2 = 13x + 56<BR>\n" );
document.write( "subtract 13x and 56 from both sides of the equation to get:<BR>\n" );
document.write( "3x^2 - 13x - 56 = 0<BR>\n" );
document.write( "now your equation is in standard quadratic form.<BR>\n" );
document.write( "this factors to be:<BR>\n" );
document.write( "(3x+8) * (x-7) = 0<BR>\n" );
document.write( "you get:<BR>\n" );
document.write( "3x+8 = 0 and x-7 = 0 which results in:<BR>\n" );
document.write( "x = -(8/3) or x = 7<BR>\n" );
document.write( "plug those values in the original equation and the original equation should be true.<BR>\n" );
document.write( "example:<BR>\n" );
document.write( "when you replace x with -(8/3) your original equation becomes:<BR>\n" );
document.write( "3*(-8/3)^2 = 13(-8/3) + 56<BR>\n" );
document.write( "simplify this to get:<BR>\n" );
document.write( "21.33333 = 21.33333<BR>\n" );
document.write( "when you replace x with 7, your original equation becomes:<BR>\n" );
document.write( "3*(7)^2 = 13*7 + 56<BR>\n" );
document.write( "simplify this to get:<BR>\n" );
document.write( "147 = 147<BR>\n" );
document.write( "original equation is true (left side equals right side) in both cases so both answers satisfy the original equation.<BR>\n" );
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