document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=623560>Question 623560</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of x in the domain of f(x) = 6 &#8722; 4x for which f(x) = 8.\r<BR>\n" );
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document.write( "x = ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #392156 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=392156\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x) = 6 - 4x<BR>\n" );
document.write( "f(x) = 8<BR>\n" );
document.write( "this means that:<BR>\n" );
document.write( "8 = 6 - 4x<BR>\n" );
document.write( "subtract 6 from both sides of this equation to get:<BR>\n" );
document.write( "2 = - 4x<BR>\n" );
document.write( "divide both sides of this equation by -4 to get:<BR>\n" );
document.write( "-(2/4) = x<BR>\n" );
document.write( "value of x is equal to -(1/2)<BR>\n" );
document.write( "plug that into your original equation of:<BR>\n" );
document.write( "f(x) = 6 - 4x to get:<BR>\n" );
document.write( "f(x) = 6 - 4 * (-1/2) which becomes:<BR>\n" );
document.write( "f(x) = 6 + (4/2) which becomes:<BR>\n" );
document.write( "f(x) = 6 + 2 which becomes:<BR>\n" );
document.write( "f(x) = 8<BR>\n" );
document.write( "when x = -(1/2), f(x) = 8<BR>\n" );
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