document.write( "Question 623312: graph the relation x+lyl=3 \n" ); document.write( "
Algebra.Com's Answer #392035 by lwsshak3(11628)\"\" \"About 
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graph the relation x+lyl=3
\n" ); document.write( "rewrite equation:
\n" ); document.write( "|y|=-x+3
\n" ); document.write( "like all absolute value problems you must consider two conditions:
\n" ); document.write( "y=-x+3
\n" ); document.write( "-y=-x+3 or y=x-3
\n" ); document.write( "..
\n" ); document.write( "-x+3 is an equation of a straight line with slope=-1 and y-intercept=3
\n" ); document.write( "However, x<3 to keep y>0, so this line starts at (3,0) and continues to ∞ leftward up
\n" ); document.write( "..
\n" ); document.write( "The second condition, y=x-3, is a straight line with slope=1 and y-intercept=-3
\n" ); document.write( "Again, x<3 to keep y<0, so this line also starts at (3,0) and continues to ∞ leftward down
\n" ); document.write( "..
\n" ); document.write( "So what you have is a \"V-shape\" curve opening leftward with the apex at (3,0)
\n" ); document.write( "..
\n" ); document.write( "Sorry, I don't have the means to draw the graph for you. Hope this helps.
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