document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=623270>Question 623270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have no idea how to do these, but its solving linear systems.\r<BR>\n" );
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document.write( "1)   35x+y=20<BR>\n" );
document.write( "     1.5x-0.1y=18\r<BR>\n" );
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document.write( "2)   x+(1/3y)=-2<BR>\n" );
document.write( "     -8x-(2/3y)=4\r<BR>\n" );
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document.write( "Would you mind showing the work? as stated before, I have no idea how to do these, so anything to help me understand would be much appreciated. Thank you!\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #392015 by </B><A HREF=/tutors/aboutme.mpl?userid=smmoore><B>smmoore(10)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=smmoore><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=smmoore><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=392015\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> okay i love doing these so hopfully this helps.<BR>\n" );
document.write( "First of all when solving a system of linear equations what you are trying to do is to find where the two equations intersect or where their lines cross eachother. for the first set i think the easiest way to solve them is by substitution, which is where you get one letter by its self and then plug that new equation into the other one. then you take the value that you found and plug it back into one of the equations to find the other missing value.\r<BR>\n" );
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document.write( "35x+y=20         <BR>\n" );
document.write( "1.5x-0.1y=18\r<BR>\n" );
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document.write( "first i want to take the first equation and get y alone:<BR>\n" );
document.write( "35x+y=20<BR>\n" );
document.write( "-35x    -35x<BR>\n" );
document.write( "this gives you y= -35x+20\r<BR>\n" );
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document.write( "the next step is to put -35x+20 in for where ever you see y in the second equation.\r<BR>\n" );
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document.write( "so that means that: 1.5x-0.1(-35x+20)=18   then solve it<BR>\n" );
document.write( "                    1.5x+3.5x-2=18     combine like terms and solve<BR>\n" );
document.write( "                    5x-2=18<BR>\n" );
document.write( "                      +2  +2   that gives you 5x=20  then divide to get x alone ; 5x/5=x and 20/5=4          so x=4\r<BR>\n" );
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document.write( "then the next step is to put 4 in place of x in one of the original equations. i think the first one is easier, but you can choose either one.\r<BR>\n" );
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document.write( "35x+y=20       so putting 4 in for x i get:  35(4)+y=20    then solve<BR>\n" );
document.write( "                                             140+y=20<BR>\n" );
document.write( "                                            -140   -140  that gives me:<BR>\n" );
document.write( "                                       y= -120<BR>\n" );
document.write( "after solving for x and y i know that the solution is (4,-120) which is the coordinates of the intersecting point, or (x,y)<BR>\n" );
document.write( "but sometimes you can just put what x equals and what y is seperately: x=4 and y=-120\r<BR>\n" );
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document.write( "for #2 equations i will do the exact same thong but with the different numbers.<BR>\n" );
document.write( "this time i will get x alone first.\r<BR>\n" );
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document.write( "x+(1/3y)=-2<BR>\n" );
document.write( "-8x-(2/3y)=4<BR>\n" );
document.write( "           \r<BR>\n" );
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document.write( " x+(1/3y)=-2<BR>\n" );
document.write( "   -(1/3)y  -(1/3)y   which equals: x= -(1/3)y-2<BR>\n" );
document.write( "Put that un for x in the second equation\r<BR>\n" );
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document.write( "-8(-(1/3)y-2)-(2/3)y=4   solve and combine like terms<BR>\n" );
document.write( "(8/3y)+16-(2/3y)=4    (8/3y)-(3/3y)=(5/3y)<BR>\n" );
document.write( " (5/3y)+16=4<BR>\n" );
document.write( "        -16  -16<BR>\n" );
document.write( "(5/3y)= -12    5/3y /5/3=y     -12/(5/3)= -7.2<BR>\n" );
document.write( "    y= -7.2\r<BR>\n" );
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document.write( "we have the y value, now put -7.2 in for y in the first equation\r<BR>\n" );
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document.write( "x+(1/3)*(-7.2)= -2<BR>\n" );
document.write( "x-2.4= -2<BR>\n" );
document.write( " +2.4   +2.4<BR>\n" );
document.write( "x=0.4\r<BR>\n" );
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document.write( "x= 0.4   and   y= -7.2\r<BR>\n" );
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document.write( "but the coordinate answer is (0.4,-7.2)<BR>\n" );
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