document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=623270>Question 623270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have no idea how to do these, but its solving linear systems.\r<BR>\n" );
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document.write( "1)   35x+y=20<BR>\n" );
document.write( "     1.5x-0.1y=18\r<BR>\n" );
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document.write( "2)   x+(1/3y)=-2<BR>\n" );
document.write( "     -8x-(2/3y)=4\r<BR>\n" );
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document.write( "Would you mind showing the work? as stated before, I have no idea how to do these, so anything to help me understand would be much appreciated. Thank you!\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #392014 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=392014\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have no idea how to do these, but its solving linear systems. <BR>\n" );
document.write( "1) 35x+y=20<BR>\n" );
document.write( "1.5x-0.1y=18<BR>\n" );
document.write( "multiply 2nd equation by 10 so the coefficient of y=that of the first equation<BR>\n" );
document.write( "35x+y=20<BR>\n" );
document.write( "15x-y=180<BR>\n" );
document.write( "add<BR>\n" );
document.write( "50x=200<BR>\n" );
document.write( "x=4<BR>\n" );
document.write( "plug in x=4 into first equation to solve for y<BR>\n" );
document.write( "35*4+y=20<BR>\n" );
document.write( "140+y=20<BR>\n" );
document.write( "y=-120<BR>\n" );
document.write( "check answers using 2nd equation<BR>\n" );
document.write( "15*4-(-120)=60+120=180 (ok)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "2) x+(1/3y)=-2<BR>\n" );
document.write( "-8x-(2/3y)=4<BR>\n" );
document.write( "multiply 1st equation by 2 so the coefficient of y=that of the 2nd equation<BR>\n" );
document.write( "2x+(2/3y)=-4<BR>\n" );
document.write( "-8x-(2/3y)=4<BR>\n" );
document.write( "add<BR>\n" );
document.write( "-6x=0<BR>\n" );
document.write( "x=0<BR>\n" );
document.write( "use 2nd equation to solve for y<BR>\n" );
document.write( "0-2y/3=4<BR>\n" );
document.write( "-2y=12<BR>\n" );
document.write( "y=-6<BR>\n" );
document.write( "check answers using 1st equation<BR>\n" );
document.write( "0+2*-6/3=-4 (ok) </SPAN>\n" );
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