document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=623246>Question 623246</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains, 390 miles apart, start traveling toward each other at the same time and meet 3 hours later.  If the speed of one train is 30 mph faster than the other, find the speed of each. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #392005 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=392005\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two trains, 390 miles apart, start traveling toward each other at the same time and meet 3 hours later. If the speed of one train is 30 mph faster than the other, find the speed of each.<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x=speed of slower train<BR>\n" );
document.write( "x+30 =speed of faster train<BR>\n" );
document.write( "distance=travel time*speed<BR>\n" );
document.write( "..<BR>\n" );
document.write( "3x+3(x+30)=390<BR>\n" );
document.write( "3x+3x+90=390<BR>\n" );
document.write( "6x+300<BR>\n" );
document.write( "x=50<BR>\n" );
document.write( "x+30=80<BR>\n" );
document.write( "speed of slower train=50 mph<BR>\n" );
document.write( "speed of faster train=80 mph </SPAN>\n" );
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