document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=623176>Question 623176</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two-digir number is 12. If the digits are reversed, the new number is 18 more than the original number. Find the original number.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #391990 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=391990\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two-digir number is 12. If the digits are reversed, the new number is 18 more than the original number. Find the original number.<BR>\n" );
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document.write( "let u=units digit<BR>\n" );
document.write( "let t=tens digit<BR>\n" );
document.write( "t+u=12<BR>\n" );
document.write( "t=12-u<BR>\n" );
document.write( "10t+u=original number<BR>\n" );
document.write( "10u+t=new number<BR>\n" );
document.write( "original number+18=new number<BR>\n" );
document.write( "10t+u+18=10u+t<BR>\n" );
document.write( "10(12-u)+u+18=10u+(12-u)<BR>\n" );
document.write( "120-10u+u+18=10u+12-u<BR>\n" );
document.write( "18u=126<BR>\n" );
document.write( "u=7<BR>\n" );
document.write( "t=12-7=5<BR>\n" );
document.write( "..<BR>\n" );
document.write( "original number=57<BR>\n" );
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