document.write( "Question 623247: A total of $4000 was invested, part of it at 8% interest and the remainder at 9%. If the yearly interest amounted to $350, how much was invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #391985 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,  ·
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document.write( "A total of $4000 was invested, part of it at 8% interest and the remainder at 9%.  
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document.write( "If the yearly interest amounted to $350, how much was invested at each rate?
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document.write( " .08·x + .09($4000-x)= $350
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document.write( "            -.01·x = $350 - $360
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document.write( "                 x = -$10/-.01
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document.write( "                 x = $1000, amount at 8%,  $3000 the amount at 9%
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document.write( "and
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document.write( "CHECKING our Answer***
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document.write( "  $80 + $270 = $350 \n" );
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