document.write( "Question 623236: THE LENGTH OF A FIELD IS 6FT MORE THAN TWICE ITS WIDTH,IF THE PERIMETER OF THE FIELD IS 228FT FIND THE DIMENSIONS OF THE FIELD \n" ); document.write( "

Algebra.Com's Answer #391973 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Please do not use Caps on this Site as it makes it more difficult or read. TY
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document.write( "The length of a field is 6' more that twice it width,
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document.write( "If the perimeter is 228', find the dimensions of the field.
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document.write( " P = 2L + 2W 
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document.write( "Question states***
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document.write( "  2(2x+6') + 2x = 228'
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document.write( "      6x = 216
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document.write( "       x = 36', the width and the length is 78'
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document.write( "and
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document.write( "CHECKING our Answer***
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