document.write( "Question 57442: 1)1. Solve the equation 3(2x-1) + x = 5x+3.
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document.write( "a. 0
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document.write( "b. 3
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document.write( "c. 3/2
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document.write( "d. no solution
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document.write( "2)2. Use the quadratic formula to solve y2+10y+24 = 0.
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document.write( "3)3. Solve by factoring: a2 -5a-14 = 0.
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document.write( "a. 5, 14
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document.write( "b. -7, 2
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document.write( "c. 2, 7
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document.write( "d. 7, -2
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document.write( "4)4. Solve the inequality 3x + 5< with - under < 7 . Write the solution using interval notation.
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document.write( "a. (- ∞ , 4]
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document.write( "b. [4, ∞ )
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document.write( "c. (- ∞ , 2/3]
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document.write( "d. [2/3, ∞ )
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document.write( "
Algebra.Com's Answer #39193 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! 1)1. Solve the equation 3(2x-1) + x = 5x + 3. \n" ); document.write( "6x - 3 + x = 5x + 3 \n" ); document.write( "7x - 3 = 5x + 3 \n" ); document.write( "2x = 6 \n" ); document.write( "x = 3 \n" ); document.write( "b. \n" ); document.write( "2)2. Use the quadratic formula to solve y2+10y+24 = 0. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "3)3. Solve by factoring: a2 - 5a - 14 = 0. \n" ); document.write( "(x - 7)(x + 2) = 0 \n" ); document.write( "x = 7 and x = -2 \n" ); document.write( "d. \n" ); document.write( "4)4. Solve the inequality 3x + 5< with - under < 7 . Write the solution using interval notation. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(- \n" ); document.write( "c. \n" ); document.write( " |