document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=623191>Question 623191</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Stephanie wishes to make 6 litres of drink containing 60% orange juice by mixing plain water and concentrate which is 90% orange juice. How many litres of plain water and concentrate should she mix? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #391919 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=391919\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Stephanie wishes to make 6 litres of drink containing 60% orange juice by mixing plain water and concentrate which is 90% orange juice. How many litres of plain water and concentrate should she mix?<BR>\n" );
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document.write( "Let x = amount (litres) of plain water<BR>\n" );
document.write( "then<BR>\n" );
document.write( "6-x = amount (litres) of concentrate<BR>\n" );
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document.write( ".90(6-x) = .60(6)<BR>\n" );
document.write( "5.4-.90x = 3.6<BR>\n" );
document.write( "-.90x = -1.8<BR>\n" );
document.write( "x = -1.8/(-.90)<BR>\n" );
document.write( "x = 2 litres (water)<BR>\n" );
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document.write( "Concentrate:<BR>\n" );
document.write( "6-x = 6-2 = 4 litres\r<BR>\n" );
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document.write( " </SPAN>\n" );
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