document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=623186>Question 623186</A>: <I><SPAN STYLE=\"word-break: break-all;\"> per favore mi potete aiutere perchè non ho capito questo problema:<BR>\n" );
document.write( "in un rettangolo una dimensione è il triplo dell' altra e la loro somma misura 120 cm. calcola il perimetro di un triangolo equilatero il cui lato è congruente al doppio della dimensione minore del rettangolo.<BR>\n" );
document.write( "grazie mille<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #391918 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=391918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please can I aiutere because I did not understand this problem:<BR>\n" );
document.write( " a dimension of a rectangle is three times the 'other and their sum is 120 cm.<BR>\n" );
document.write( "L = 3W<BR>\n" );
document.write( "L + W = 120 cm<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "3W + W = 120<BR>\n" );
document.write( "W = 30 cm<BR>\n" );
document.write( "L = 90 cm<BR>\n" );
document.write( "---------<BR>\n" );
document.write( " calculates the perimeter of an equilateral triangle whose side is congruent to twice the minor dimension of the rectangle.<BR>\n" );
document.write( "s = 30 cm<BR>\n" );
document.write( "P = 3s = 90 cm </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );