document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=623171>Question 623171</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are supplementary. the larger is 6 degrees more than twice the smaller angle. find the two angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #391915 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=391915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> two angles are supplementary. the larger is 6 degrees more than twice the smaller angle. find the two angles<BR>\n" );
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document.write( "Let x = smaller angle<BR>\n" );
document.write( "then<BR>\n" );
document.write( "2x+6 = larger angle<BR>\n" );
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document.write( "x + 2x+6 = 180<BR>\n" );
document.write( "3x+6 = 180<BR>\n" );
document.write( "3x = 174<BR>\n" );
document.write( "x = 58 degrees (smaller angle)<BR>\n" );
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document.write( "Larger angle:<BR>\n" );
document.write( "2x+6 = 2(58)+6 = 116+6 = 122 degrees </SPAN>\n" );
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