document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=623175>Question 623175</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Among two supplementry angles, the measure of the large angle 36 degree more than the smaller angle.find their measures. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #391914 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=391914\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Among two supplementry angles, the measure of the large angle 36 degree more than the smaller angle.find their measures.<BR>\n" );
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document.write( "Let x = measure of smaller angle<BR>\n" );
document.write( "then<BR>\n" );
document.write( "x+36 = measure of larger angle<BR>\n" );
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document.write( "x + x+36 = 180<BR>\n" );
document.write( "2x+36 = 180<BR>\n" );
document.write( "2x = 144<BR>\n" );
document.write( "x = 72 degrees (smaller angle)<BR>\n" );
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document.write( "Larger angle:<BR>\n" );
document.write( "x+36 = 72+36 = 108 degrees (larger angle)<BR>\n" );
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