document.write( "Question 623177: Paul's age is two years more than twice Mark's age. The sum of their ages is 32 years. How old are Paul and Mark? \n" ); document.write( "
Algebra.Com's Answer #391913 by lenny460(1073)\"\" \"About 
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Let Mark's age be n\r
\n" ); document.write( "\n" ); document.write( "Let Paul's age be n * 2 + 2 = 2n + 2\r
\n" ); document.write( "\n" ); document.write( "Combine their ages:\r
\n" ); document.write( "\n" ); document.write( "n + 2n + 2 = 32\r
\n" ); document.write( "\n" ); document.write( "Combine like terms:\r
\n" ); document.write( "\n" ); document.write( "n + 2n = 3n\r
\n" ); document.write( "\n" ); document.write( "3n + 2 = 32\r
\n" ); document.write( "\n" ); document.write( "Subtract 2 from each side of the equation\r
\n" ); document.write( "\n" ); document.write( "3n + 2 - 2 = 32 - 2\r
\n" ); document.write( "\n" ); document.write( "Combine like terms:\r
\n" ); document.write( "\n" ); document.write( "2 - 2 = 0\r
\n" ); document.write( "\n" ); document.write( "32 - 2 = 30\r
\n" ); document.write( "\n" ); document.write( "3n = 30\r
\n" ); document.write( "\n" ); document.write( "Divide each side by 3\r
\n" ); document.write( "\n" ); document.write( "3n/3 = 30/3\r
\n" ); document.write( "\n" ); document.write( "n = 10\r
\n" ); document.write( "\n" ); document.write( "2n + 2 = 2 * 10 + 2 \r
\n" ); document.write( "\n" ); document.write( "= 20 + 2 = 22\r
\n" ); document.write( "\n" ); document.write( "Therefore:\r
\n" ); document.write( "\n" ); document.write( "Mark is 10 years old and\r
\n" ); document.write( "\n" ); document.write( "Paul is 22 years old.
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