document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57155>Question 57155</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. If x = 3 and x = -5, then form a quadratic equation. \r<BR>\n" );
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document.write( "2. What type of solution do you get for quadratic equations where D < 0? Give reasons for your answer. Also provide an example of such a quadratic equation and find the solution of the equation. \r<BR>\n" );
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document.write( "3. Create a real-life situation that fits into the equation (x + 3)(x - 4) = 0 and express the situation as the same equation. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39180 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39180\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If x = 3 and x = -5, then form a quadratic equation.<BR>\n" );
document.write( "FOIL (x-3)(x+5) = x^2 + 2x -15 = 0<BR>\n" );
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document.write( "2. What type of solution do you get for quadratic equations where D < 0? Give reasons for your answer. <BR>\n" );
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document.write( "The equation has two complex number solutions. The Discriminant is part of the quadratic formula, so you end up with the square root of a neg number.<BR>\n" );
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document.write( "Also provide an example of such a quadratic equation and find the solution of the equation.<BR>\n" );
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document.write( "2x^2 - x + 5 = 0<BR>\n" );
document.write( "Using the quadratic formula your solutions are:<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281-i%2ASqRt%2839%29%29%2F4 ALIGN=MIDDLE  ALT=\"%281-i%2ASqRt%2839%29%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2Bi%2ASqRt%2839%29%29%2F4 ALIGN=MIDDLE  ALT=\"%281%2Bi%2ASqRt%2839%29%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "3. Create a real-life situation that fits into the equation (x + 3)(x - 4) = 0 and express the situation as the same equation:<BR>\n" );
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document.write( "The  area of a rectangle is 12 sq ft; where the width is 1 ft shorter than the<BR>\n" );
document.write( " width: W  = (L - 1)<BR>\n" );
document.write( "Area = L * (L-1) = 12<BR>\n" );
document.write( "L^2 - L - 12 = 0<BR>\n" );
document.write( "(L + 3)(L - 4) = 0<BR>\n" );
document.write( "        L = +4  </SPAN>\n" );
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