document.write( "Question 622976: Paul and his brothers Ted and Al worked out one day that their father was 3 times as old as Ted. Also that, in three years time, he would be three times as old as Paul would be, and that in 6 years time he would be twice as old as Al would be. Al was two years older than Ted.
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Algebra.Com's Answer #391775 by ankor@dixie-net.com(22740)\"\" \"About 
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Write an equation for each statement:
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\n" ); document.write( "Paul and his brothers Ted and Al worked out one day that their father was 3 times as old as Ted.
\n" ); document.write( "f + 3t
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\n" ); document.write( "Also that, in three years time, he would be three times as old as Paul would be,
\n" ); document.write( "f + 3 = 3(p+3)
\n" ); document.write( "f + 3 = 3p + 9
\n" ); document.write( "f = 3p + 9 - 3
\n" ); document.write( "f = 3p + 6
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\n" ); document.write( "and that in 6 years time he would be twice as old as Al would be.
\n" ); document.write( "f + 6 = 2(a+6)
\n" ); document.write( "f + 6 = 2a + 12
\n" ); document.write( "f = 2a + 12 - 6
\n" ); document.write( "f = 2a + 6
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\n" ); document.write( "Al was two years older than Ted.
\n" ); document.write( "a = t + 2
\n" ); document.write( "In the equation f = 2a + 6 replace f with 3t
\n" ); document.write( "3t = 2a + 6
\n" ); document.write( "Replace a with (t+2),find t
\n" ); document.write( "3t = 2(t+2) + 6
\n" ); document.write( "3t = 2t + 4 + 6
\n" ); document.write( "3t - 2t = 10
\n" ); document.write( "t = 10 yrs is Teds present age
\n" ); document.write( "then
\n" ); document.write( "3(10) = 30 yrs is father's age, which all they wish to know
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