document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57424>Question 57424</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 8(t-3) + 4t= 6(2t+1)-10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #39176 by </B><A HREF=/tutors/aboutme.mpl?userid=funmath><B>funmath(2933)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=funmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=39176\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8(t-3) + 4t= 6(2t+1)-10  First simplify both sides following the order of operation. (PEMDAS, let me know if you don't know what that is.)<BR>\n" );
document.write( "8t+8(-3)+4t=6(2t)+6(1)-10<BR>\n" );
document.write( "8t-24+4t=12t+6-10<BR>\n" );
document.write( "12t-24=12t-4  Now try to get your t's on one side of the = sign, within the rules of algebra.<BR>\n" );
document.write( "-12t+12t-24=-12t+12t-4<BR>\n" );
document.write( "-24=-4  Your variables were eliminated and -24 does not = -4, therefore there is no solution.<BR>\n" );
document.write( "Happy Calculating!!! </SPAN>\n" );
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