document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=622902>Question 622902</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A silversmith mixed 25 g of a 80% silver alloy with 50 g of a 25% silver alloy. What is the percent concentration of the resulting alloy? (Round to the nearest tenth of a percent.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #391747 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=391747\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A silversmith mixed 25 g of a 80% silver alloy with 50 g of a 25% silver alloy. What is the percent concentration of the resulting alloy? (Round to the nearest tenth of a percent.)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = concentration<BR>\n" );
document.write( "then<BR>\n" );
document.write( ".80(25) + .25(50) = x(25+50)<BR>\n" );
document.write( "20 + 12.5 = x(75)<BR>\n" );
document.write( "32.5 = x(75)<BR>\n" );
document.write( "32.5/75 = x<BR>\n" );
document.write( "0.433 = x<BR>\n" );
document.write( "43.3% = x </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );