document.write( "Question 622926: The sum of the ages of two boys is 18. If 4 times the younger boy's age is subtracted from 3 times the older boy's age, the difference is 12. What are the ages of the two boys? \n" ); document.write( "
Algebra.Com's Answer #391708 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
The sum of the ages of two boys is 18. If 4 times the younger boy's age is subtracted from 3 times the older boy's age, the difference is 12. What are the ages of the two boys?
\n" ); document.write( "**
\n" ); document.write( "let x=older boy's age
\n" ); document.write( "18-x=younger boy's age
\n" ); document.write( "..
\n" ); document.write( "3x-4(18-x)=12
\n" ); document.write( "3x-72+4x=12
\n" ); document.write( "7x=84
\n" ); document.write( "x=12
\n" ); document.write( "18-x=6
\n" ); document.write( "..
\n" ); document.write( "older boy's age=12
\n" ); document.write( "younger boy's age=6 \n" ); document.write( "
\n" );