document.write( "Question 622885: Shreya mixed together 3 L of brand A fruit drink and 5 L of brand B fruit drink which contains 50% fruit juice. Find the percent of fruit juice in brand A if the mixture con tainted 44% fruit juice. \n" ); document.write( "

Algebra.Com's Answer #391682 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = liters of juice in 3 L of brand A
\n" ); document.write( " $\"+.5%2A5+=+2.5+\"$ liters of juice in 5 L of brand B
\n" ); document.write( "------------
\n" ); document.write( " $\"+%28+x+%2B+2.5+%29+%2F+%28+3+%2B+5+%29+=+.44+\"$
\n" ); document.write( " $\"+%28+x+%2B+2.5+%29+%2F+8+=+.44+\"$
\n" ); document.write( " $\"+x+%2B+2.5+=+3.52+\"$
\n" ); document.write( " $\"+x+=+3.52+-+2.5+\"$
\n" ); document.write( " $\"+x+=+1.02+\"$
\n" ); document.write( "There are 1.02 liters of juice in 3 L of brand A
\n" ); document.write( "-----------
\n" ); document.write( " $\"+1.02+%2F+3+=+.34+\"$
\n" ); document.write( "Brand A mixture has 34% fruit juice
\n" ); document.write( "check answer:
\n" ); document.write( " $\"+%28+x+%2B+2.5+%29+%2F+8+=+.44+\"$
\n" ); document.write( " $\"+%28+1.02+%2B+2.5+%29+%2F+8+=+.44+\"$
\n" ); document.write( " $\"+3.52+%2F+8+=+.44+\"$
\n" ); document.write( " $\"+3.52+=+8%2A.44+\"$
\n" ); document.write( " $\"+3.52+=+3.52+\"$
\n" ); document.write( "OK \n" ); document.write( "

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