document.write( "Question 622815: please help me find the exact values of:\r
\n" ); document.write( "\n" ); document.write( "tan2u\r
\n" ); document.write( "\n" ); document.write( "given sinu= -4/5 and pi< u < 3pi/2
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Algebra.Com's Answer #391646 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
There is a formula that expresses tan(2u) in terms of tan(u):
\n" ); document.write( "\"tan%282u%29+=+%282%2Atan%28u%29%29%2F%281-tan%5E2%28u%29%29\"
\n" ); document.write( "So if we can find tan(u) we can use this formula to find tan(2u).

\n" ); document.write( "We are given that sin(u) = -4/5. We can use one of the Pythagorean identities, \"cos%5E2%28a%29+=+1-+sin%5E2%28a%29\", to use sin(u) to find cos(u). And once we have cos(u) we can use the fact that tan(u) = sin(u)/cos(u) to find tan(u).

\n" ); document.write( "\"cos%5E2%28u%29+=+1+-+sin%5E2%28u%29\"
\n" ); document.write( "\"cos%5E2%28u%29+=+1+-+%28-4%2F5%29%5E2\"
\n" ); document.write( "\"cos%5E2%28u%29+=+1+-+16%2F25\"
\n" ); document.write( "\"cos%5E2%28u%29+=+25%2F25+-+16%2F25\"
\n" ); document.write( "\"cos%5E2%28u%29+=+9%2F25\"
\n" ); document.write( "Now we find the square root of each side. But which square root should we use? The positive one or the negative one? Well, since we are told that \"pi%3C+u+%3C+3pi%2F2\" we know that u terminates in the 3rd quadrant. And in the 3rd quadrant cos is negative. So we should use the negative square root:
\n" ); document.write( "\"cos%28u%29+=+-sqrt%289%2F25%29\"
\n" ); document.write( "\"cos%28u%29+=+-3%2F5\"

\n" ); document.write( "Now we can find tan(u):
\n" ); document.write( "\"tan%28u%29+=+sin%28u%29%2Fcos%28u%29\"
\n" ); document.write( "\"tan%28u%29+=+%28-4%2F5%29%2F%28-3%2F5%29\"
\n" ); document.write( "\"tan%28u%29+=+4%2F3\"

\n" ); document.write( "Now we can find tan(2u):
\n" ); document.write( "\"tan%282u%29+=+%282%2Atan%28u%29%29%2F%281-tan%5E2%28u%29%29\"
\n" ); document.write( "\"tan%282u%29+=+%282%2A%284%2F3%29%29%2F%281-%284%2F3%29%5E2%29\"
\n" ); document.write( "\"tan%282u%29+=+%288%2F3%29%2F%281-%2816%2F9%29%29\"
\n" ); document.write( "\"tan%282u%29+=+%288%2F3%29%2F%289%2F9-%2816%2F9%29%29\"
\n" ); document.write( "\"tan%282u%29+=+%288%2F3%29%2F%28-7%2F9%29\"
\n" ); document.write( "When we divide fractions we change it to multiplying by the reciprocal:
\n" ); document.write( "\"tan%282u%29+=+%288%2F3%29%2A%28-9%2F7%29\"
\n" ); document.write( "\"tan%282u%29+=+-24%2F63\"
\n" ); document.write( "which reduces to:
\n" ); document.write( "\"tan%282u%29+=+-8%2F21\"
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