document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=622806>Question 622806</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The monthly payment p on a mortgage varies directly with the amount borrowed B. If the monthly payment on a 30-year mortgage is $7.30 for every $1000 borrowed, find a linear function that relates the monthly payment p to the amount B for a mortgage with the same terms. Then find the monthly payment p when the amount borrowed is $194,000.\r<BR>\n" );
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document.write( "I come up with p= B/219; $885.84 am I right? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #391631 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=391631\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> $7.30 for every $1000 (B) borrowed means $7.30B...multiply the number of thousands borrowed by $7.30.  p=7.3B<P><BR>\n" );
document.write( "In this case it's p=7.3*194 = $1416.20.<BR>\n" );
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