document.write( "Question 622619: A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as much in the lower-yielding account because it is less risky. His annual interest is $4,180. How much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #391597 by math-vortex(648)![]() ![]() You can put this solution on YOUR website! Hi, there-- \n" ); document.write( ". \n" ); document.write( "We can use algebra to solve this. \n" ); document.write( ". \n" ); document.write( "Let x be the amount of money invested at 6% simple interest. \n" ); document.write( "Let y be the amount of money invested at 10% simple interest. \n" ); document.write( ". \n" ); document.write( "Express the interest rates in decimal form: 6% = 0.06 and 10% = 0.10 \n" ); document.write( ". \n" ); document.write( "The amount of interest earned on the the first account is the interest rate times the amount invested, or 0.06x. \n" ); document.write( ". \n" ); document.write( "Likewise, the amount of interest earned on the second account is its interest rate times the amount invested, or 0.10*y. \n" ); document.write( ". \n" ); document.write( "Now we need to write two equations using the information in the problem to model the situation. \n" ); document.write( ". \n" ); document.write( "The man puts twice as much in the lower-yielding account because it is less risky. In other words, \n" ); document.write( "[the amount invested at 6%] = [2] * [amount invested at 10%] \n" ); document.write( ". \n" ); document.write( "In algebra, we can write this relationship as \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The amount the man earns in interest is $4,180. In other words, \n" ); document.write( "[interest earned at 6%] + [interest earned at 10%] = [$4,180] \n" ); document.write( ". \n" ); document.write( "In algebra, we can write \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "We have a system of two equations and two variables. We will use the substitution method to solve for x and y. The first equation states that x=2y, so we substitute 2y for x in the second equation. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now simplify and solve for x. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Divide both sides of the equation by 0.22 \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "In the context of this problem, y=19000 means that the man invested $19,000 in the account earning 10% simple interest. Since he invested twice as much in the account eating 6%, he must have invested $38,000 at 6%. \n" ); document.write( ". \n" ); document.write( "The final step is to check that this allocation of the money actually earns $4,180 in total interest. \n" ); document.write( ". \n" ); document.write( "$38,000 at 6% interest earns $2,280 since 0.06*38000=2280 \n" ); document.write( "$19,000 invested at 10% interest earns $1,900 since 0.10*19000=1900 \n" ); document.write( "$2,280+1,900 is $4,180 so everything checks out. \n" ); document.write( ". \n" ); document.write( "That's it. Feel free to email if you have questions about any part of this explanation. \n" ); document.write( ". \n" ); document.write( "Ms.Figgy \n" ); document.write( "math.in.the.vortex@gmail.com \n" ); document.write( " |