document.write( "Question 622726: With a y-intercept 10, x-intercept 2, and equation of axis of symmetry x-3 = 0, find the graph equation in standard form.
\n" ); document.write( "So I've got two points (0, 10) (2, 0) and half of the vertex (3, k). I don't know how to get this.
\n" ); document.write( "The equation is y = a(x-h)^2 + k
\n" ); document.write( "Either of the two points could be labelled x and y. I'll use the x-intercept (2, 0). The vertex is used for h, k.
\n" ); document.write( "So I've got 0 = a(2 - 3)^2 + k
\n" ); document.write( "Two unsolved for variables. Not sure what to do. \n" ); document.write( "

Algebra.Com's Answer #391559 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "parabola: with axis of symmetry x = 3, passing thru (0,10) and (2,0)
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document.write( "y = a(x-h)^2 + k  
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document.write( "|Note: Parabola with this format.. always opens along its axis of symmetry x = h
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document.write( "y = a(x-3)^2 + k   Pt(2,0)
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document.write( "0 = a(-1)^2 + k
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document.write( "-k = a
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document.write( "10 = a(-3)^2 + k     Pt(0,10)
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document.write( "(10-k)/9 = a
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document.write( "(10-k)/9 = -k
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document.write( "  10-k = -9k
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document.write( "    8k = -10
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document.write( "     k = -10/8 = -5/4  and a = 5/4
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document.write( "  \n" );
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