document.write( "Question 622707: Parabola questions are the hardest can someone help me figure this out show steps please. \r
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\n" ); document.write( "\n" ); document.write( "The parabola given by the equation y=-x^2+8 x-8 has its vertex at (h,k) for:
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Algebra.Com's Answer #391547 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "y = -x^2+ 8x- 8 |putting into Vertex form \"a%28x+-+h%29%5E2+%2B+k\" by completing the Square
\n" ); document.write( "y = -(x-4)^2 + 16 - 8
\n" ); document.write( "y = -(x-4)^2 + 8 V(4,8) (h is 4 and k is 8)\r
\n" ); document.write( "\n" ); document.write( "Note: In general: y = ax^2 + bx + c
\n" ); document.write( "If you need a shortcut on this: y = -x^2+ 8x- 8, (a = -1, b = 8 and c = -8)
\n" ); document.write( "In general: y = ax^2 + bx + c .... going to y = a(x-h)^2 + k ... following is true
\n" ); document.write( " \"h+=+-b%2F2a+=+-8%2F-2+=+4\"
\n" ); document.write( " \"k+=+c+-+b%5E2%2F4a+=++-8+-+64%2F-4+=+8\"
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