document.write( "Question 622715: where is the transverse axis for this hyperbola?
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Algebra.Com's Answer #391544 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi,
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document.write( "transverse axis for hyperbola:
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document.write( "\"8y%5E2-5x%5E2=40\"
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document.write( "\"+y%5E2%2F5+-+x%5E2%2F8+=+1\" C(0,0) Vertices (0,±\"sqrt%285%29\") 
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document.write( "Opens Up and Down along x = 0 or the y-axis. tranverse axis is the y-axis.
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document.write( "See below descriptions of various conics                         
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document.write( "Standard Form of an Equation of a Circle is \"%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\" 
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document.write( "where Pt(h,k) is the center and r is the radius\r
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document.write( " Standard Form of an Equation of an Ellipse is \"%28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+\" 
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document.write( "where Pt(h,k) is the center. (a positioned to correspond with major axis)
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document.write( " a and b  are the respective vertices distances from center
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document.write( " and ±\"sqrt%28a%5E2-b%5E2%29\"are the foci distances from center: a > b\r
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document.write( "Standard Form of an Equation of an Hyperbola opening right and  left is:
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document.write( "  \"%28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1\" where Pt(h,k) is a center  with vertices 'a' units right and left of center 
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document.write( "and foci \"sqrt%28a%5E2%2Bb%5E2%29\" units right and left of center along y = k\r
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document.write( "Standard Form of an Equation of an Hyperbola opening up and down is:
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document.write( "  \"%28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1\" where Pt(h,k) is a center  with vertices 'b' units up and down from center, 
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document.write( "and foci \"sqrt%28a%5E2%2Bb%5E2%29\"units units up and down from center, along x = h\r
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document.write( "the vertex form of a Parabola opening up(a>0) or down(a<0), \"y=a%28x-h%29%5E2+%2Bk\" where(h,k) is the vertex.
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document.write( "The standard form is \"%28x+-h%29%5E2+=+4p%28y+-k%29\", where  the focus is (h,k + p)\r
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document.write( "the vertex form of a Parabola opening right(a>0) or left(a<0), \"x=a%28y-k%29%5E2+%2Bh\" where(h,k) is the vertex.
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document.write( "The standard form is \"%28y+-k%29%5E2+=+4p%28x+-h%29\", where  the focus is (h +p,k ) \n" );
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