document.write( "Question 57406This question is from textbook Algebra: Structure and Method
\n" ); document.write( ": If Gina leaves now and drives at 66 km/h, she will reach Alton just in time for her appointment. On the other hand, if she has lunch first and leaves in 40 minutes, she will have to drive at 90 km/h to make her appointment. How far away is Alton? \n" ); document.write( "
Algebra.Com's Answer #39152 by checkley71(8403)\"\" \"About 
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66X=90(X-2/3)
\n" ); document.write( "66X=90X-90*2/3
\n" ); document.write( "66X=90X-180/3
\n" ); document.write( "66X=90X-60
\n" ); document.write( "66X-90X=-60
\n" ); document.write( "-24X=-60
\n" ); document.write( "X=-60/-24
\n" ); document.write( "X=2.5
\n" ); document.write( "66*2.5=165 KM
\n" ); document.write( "90(2.5-2/3)
\n" ); document.write( "90(11/6)
\n" ); document.write( "990/6=165 KM\r
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