document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=622629>Question 622629</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a car starts it journey at 11 am with velocity = 60km/h then an0ther car after one hour starts its journey with velocity = 80km/h. When does 2nd car cross 1st?<BR>\n" );
document.write( "a. 1 pm<BR>\n" );
document.write( "b. 1:50 pm<BR>\n" );
document.write( "c. 2 pm<BR>\n" );
document.write( "d. 2:30pm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #391510 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=391510\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rate * Time = Distance<BR>\n" );
document.write( "That's the formula you use.<BR>\n" );
document.write( "They will both have traveled the same distance when the first car crosses the second car.<BR>\n" );
document.write( "The Equation for the first car is:<BR>\n" );
document.write( "60 * T = D<BR>\n" );
document.write( "The Equation for the second car is:<BR>\n" );
document.write( "80 * (T-1) = D<BR>\n" );
document.write( "T is the number of hours the first car travels.<BR>\n" );
document.write( "T-1 is the number of hours the second car travels because the second car starts 1 hour after the first car and so is traveling 1 hour less when they cross each other.<BR>\n" );
document.write( "Your 2 equations are:<BR>\n" );
document.write( "60 * T = D<BR>\n" );
document.write( "80 * (T-1) = D<BR>\n" );
document.write( "since they are both equal to D, we can set them equal to each other to get:<BR>\n" );
document.write( "60 * T = 80 * (T-1) <BR>\n" );
document.write( "Simplify to get:<BR>\n" );
document.write( "60 * T = 80 * T - 80<BR>\n" );
document.write( "subtract 60 * T from both sides of the equation and add 80 to both sides of the equation to get:<BR>\n" );
document.write( "80 = 20 * T<BR>\n" );
document.write( "divide both sides of the equation by 20 to get:<BR>\n" );
document.write( "4 = T<BR>\n" );
document.write( "T is equal to 4 hours.<BR>\n" );
document.write( "T-1 is equal to 3 hours.<BR>\n" );
document.write( "The first car travels 4 hours at 60 kilometers per hour to travel a total distance of 240 kilometers.<BR>\n" );
document.write( "The second car travels 3 hours at 80 kilometers per hour to travel a total distance of 240 kilometers<BR>\n" );
document.write( "They will cross each other 240 miles from the start6ing point.<BR>\n" );
document.write( "This will happen 4 hours after the first car starts.<BR>\n" );
document.write( "The first car starts at 11:00 am.<BR>\n" );
document.write( "The crossing occurs as 3:00 pm.<BR>\n" );
document.write( "Unfortunately, that's not one of your answer selections.<BR>\n" );
document.write( "I double-checked the calculations and they look good.<BR>\n" );
document.write( "?????\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );