document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=622632>Question 622632</A>: <I><SPAN STYLE=\"word-break: break-all;\"> which among log (base 13)169 and log (base 23)521 is greater ?(with out using calculator)<BR>\n" );
document.write( "thanks<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #391483 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=391483\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> which among log (base 13)169 and log (base 23)521 is greater<BR>\n" );
document.write( "Using exponential form of logs:<BR>\n" );
document.write( "Base raised to log of number=number<BR>\n" );
document.write( "for first case<BR>\n" );
document.write( "13^x=169<BR>\n" );
document.write( "x=2 which is the log of 169 base 13<BR>\n" );
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document.write( "for 2nd case<BR>\n" );
document.write( "23^x=521<BR>\n" );
document.write( "x=<2 which is the log of 529 base 23 (if x=2, the number=23^2=529, so x<2)\r<BR>\n" );
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document.write( "The log of the first case>log of 2nd case<BR>\n" );
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