document.write( "Question 622580: i am having trouble solving this equation\r
\n" ); document.write( "\n" ); document.write( "how can you factor
\n" ); document.write( "2a2 + 1 + 3a
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Algebra.Com's Answer #391479 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!
i am having trouble solving this equation\r
\n" ); document.write( "\n" ); document.write( "how can you factor
\n" ); document.write( "2a2 + 1 + 3a \r
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\n" ); document.write( "\n" ); document.write( "You DID NOT submit an equation, but a trinomial instead\r
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\n" ); document.write( "\n" ); document.write( "\"2a%5E2++%2B+3a+%2B+1\"\r
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\n" ); document.write( "\n" ); document.write( "You'll need to find two factors whose PRODUCT is \"+ 2\" (product of \"c\" and \"a\", and whose sum is + 3 (coefficient of b)\r
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\n" ); document.write( "\n" ); document.write( "The two factors that satisfy this criteria are + 1, and + 2\r
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\n" ); document.write( "\n" ); document.write( "We then have: \"highlight_green%28%282a+%2B+1%29%28a+%2B+1%29%29\"...That's it!!\r
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\n" ); document.write( "\n" ); document.write( "If it's indeed an equation that you meant to post, then just set both binomials equal to 0 (zero), and solve for a to get 2 solutions.\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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