document.write( "Question 57209: 1)show me how to compute the following:
\n" ); document.write( "log_2(4)log_4(6)log_6(8)\r
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\n" ); document.write( "\n" ); document.write( "2a)write as sum and difference logs:
\n" ); document.write( "b)show log_b(A/D)=log_b(A)-log_b(D)
\n" ); document.write( "log_4[-4^3x^2(x-1)^1/2/(x+3)^3\r
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Algebra.Com's Answer #39145 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1)show me how to compute the following:
\n" ); document.write( "log_2(4)log_4(6)log_6(8)
\n" ); document.write( "I assume you are multiplying:
\n" ); document.write( "=[(log4)/(log2)]*(log8)/(log6)
\n" ); document.write( "=(log8)/(log2)
\n" ); document.write( "-----------------------
\n" ); document.write( "2a)write as sum and difference logs:
\n" ); document.write( "b)show log_b(A/D)=log_b(A)-log_b(D)
\n" ); document.write( "log_4[-4^3x^2(x-1)^1/2/(x+3)^3
\n" ); document.write( "Keep in mind this is all base 4.
\n" ); document.write( "I'll have to assume that negative is not there:
\n" ); document.write( "=log[(4^3)(2^(x-1))/(x+3)^3]
\n" ); document.write( "=3log4 +(x-1)log2 - 3log(x+3)
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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