document.write( "Question 622507: please help me verify:\r
\n" ); document.write( "\n" ); document.write( "cos^3sin^2= (sin^2-sin^4)cosx
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Algebra.Com's Answer #391440 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
please help me verify:
\n" ); document.write( "cos^3sin^2= (sin^2-sin^4)cosx
\n" ); document.write( "starting with right side:
\n" ); document.write( "(sin^2-sin^4)cosx
\n" ); document.write( "=sin^2(1-sin^2)cos
\n" ); document.write( "=sin^2*cos^2*cos
\n" ); document.write( "=cos^3sin^2
\n" ); document.write( "verified:
\n" ); document.write( "right side=left side
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\n" ); document.write( "
\n" );