document.write( "Question 57398: how do you go about solving the following:\r
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document.write( "2x+y-z=5
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document.write( "3x-y+2z=-1
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document.write( "x-y-z=19\r
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document.write( "try to solve this system using either elimination or substitution:
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Algebra.Com's Answer #39144 by Nate(3500) ![]() You can put this solution on YOUR website! 3x - y + 2z = -1 \n" ); document.write( "-x + y + z = -19 \n" ); document.write( "2x + 3z = -20 from elimination \n" ); document.write( "2x + y - z = 5 \n" ); document.write( "x - y - z = 19 \n" ); document.write( "3x - 2z = 24 from elimination \n" ); document.write( "(2x + 3z = -20)2 \n" ); document.write( "(3x - 2z = 24)3 \n" ); document.write( "4x + 6z = -40 \n" ); document.write( "9x - 6z = 72 \n" ); document.write( "13x = 32 \n" ); document.write( "x = 32/13 \n" ); document.write( "plug: \n" ); document.write( "3x - 2z = 24 \n" ); document.write( "3(32/13) - 2z = 24 \n" ); document.write( "96/13 - 2z = 312/13 \n" ); document.write( "-2z = 216/13 \n" ); document.write( "z = -108/13 \n" ); document.write( "plug: \n" ); document.write( "x - y - z = 19 \n" ); document.write( "32/13 - y + 108/13 = 247/13 \n" ); document.write( "-y + 140/13 = 247/13 \n" ); document.write( "-y = 107/13 \n" ); document.write( "y = -107/13 \n" ); document.write( "z = -108/13 \n" ); document.write( "x = 32/13 \n" ); document.write( " |