document.write( "Question 57398: how do you go about solving the following:\r
\n" ); document.write( "\n" ); document.write( "2x+y-z=5
\n" ); document.write( "3x-y+2z=-1
\n" ); document.write( "x-y-z=19\r
\n" ); document.write( "\n" ); document.write( "try to solve this system using either elimination or substitution:
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Algebra.Com's Answer #39144 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
3x - y + 2z = -1
\n" ); document.write( "-x + y + z = -19
\n" ); document.write( "2x + 3z = -20 from elimination
\n" ); document.write( "2x + y - z = 5
\n" ); document.write( "x - y - z = 19
\n" ); document.write( "3x - 2z = 24 from elimination
\n" ); document.write( "(2x + 3z = -20)2
\n" ); document.write( "(3x - 2z = 24)3
\n" ); document.write( "4x + 6z = -40
\n" ); document.write( "9x - 6z = 72
\n" ); document.write( "13x = 32
\n" ); document.write( "x = 32/13
\n" ); document.write( "plug:
\n" ); document.write( "3x - 2z = 24
\n" ); document.write( "3(32/13) - 2z = 24
\n" ); document.write( "96/13 - 2z = 312/13
\n" ); document.write( "-2z = 216/13
\n" ); document.write( "z = -108/13
\n" ); document.write( "plug:
\n" ); document.write( "x - y - z = 19
\n" ); document.write( "32/13 - y + 108/13 = 247/13
\n" ); document.write( "-y + 140/13 = 247/13
\n" ); document.write( "-y = 107/13
\n" ); document.write( "y = -107/13
\n" ); document.write( "z = -108/13
\n" ); document.write( "x = 32/13
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