document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=622512>Question 622512</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What's the volume of a right cylinder with a diameter of 10, which I know the radius needed is 5, and the slant height 13?\r<BR>\n" );
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document.write( "The slant height throws me off. I know I need the height but how do I find the height when I'm given the slant height. i didn't even know there was slant height in a cylinder. Sorry to sound so ignorant about this. Thanks in advance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #391411 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=391411\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "Slant height has nothing whatever to do with a cylinder.  Now it is possible that they are talking about the slant height of a cone that has the same base and height as your cylinder.  Then you can use the slant height and the radius as the hypotenuse and one leg of a right triangle as inputs to Pythagoras so that you can get the height of the cone and thereby the height of the cylinder.\r<BR>\n" );
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document.write( "Hint: 5-12-13 is a Pythagorean triple.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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