document.write( "Question 622413: Five times a number plus four times a second number equal to eighty-three. The difference between the two numbers is 5. Find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #391372 by matineesuxxx(27)\"\" \"About 
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let x represent the smaller number,
\n" ); document.write( "let y represent the larger number\r
\n" ); document.write( "\n" ); document.write( "therefore,
\n" ); document.write( "\"five times a number plus four times a second number is 83\"
\n" ); document.write( "that means,
\n" ); document.write( "\"5x%2B4y=83\"
\n" ); document.write( "and if,
\n" ); document.write( "\"y-x=5\"
\n" ); document.write( "then,
\n" ); document.write( "\"y=5%2Bx\"
\n" ); document.write( "therefore, since we now know what y equals, plug it back into the equation,
\n" ); document.write( "\"5x%2B4%285%2Bx%29=83\"
\n" ); document.write( "\"5x%2B20%2B4x=83\"
\n" ); document.write( "\"9x%2B20=83\"
\n" ); document.write( "\"9x=63\"
\n" ); document.write( "\"x=63%2F9\"
\n" ); document.write( "\"x=7\"
\n" ); document.write( "now plug that x value into the equation,
\n" ); document.write( "\"y-x=5\" so that you have
\n" ); document.write( "\"y-7=5\"
\n" ); document.write( "\"y=12\"
\n" ); document.write( "NOW you can also solve this by using a system of equations.
\n" ); document.write( "the first equation is \"4y%2B5x=83\" and the second is \"y-x=5\"\r
\n" ); document.write( "\n" ); document.write( "place one on top of the other \r
\n" ); document.write( "\n" ); document.write( "\"4y%2B5x=83\"
\n" ); document.write( "\"y-x=5\"
\n" ); document.write( "now notice if you multiply \"y-x=5\" by positive 5 and add the two equations, you will be able to eliminate the x.\r
\n" ); document.write( "\n" ); document.write( "\"4y%2B5x=83\" + \"5y-5x=25\" = \"9y=108\"
\n" ); document.write( "therefore, \"y=12\" and now once again plug y in and solve for x and you get 7.
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