document.write( "Question 622402: 1.  A is 6 years older than B. In 5 years time their total age is 70. How old are they now?                                                                                                         The answer is 33 and 27, but how do you calculate this? \n" ); document.write( "
Algebra.Com's Answer #391361 by lenny460(1073)\"\" \"About 
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Let the age of A be = n + 6\r
\n" ); document.write( "\n" ); document.write( "Let the age of B be = n\r
\n" ); document.write( "\n" ); document.write( "In five years time:\r
\n" ); document.write( "\n" ); document.write( "A = n + 6 + 5\r
\n" ); document.write( "\n" ); document.write( "B = n + 5\r
\n" ); document.write( "\n" ); document.write( "(n + 6 + 5) + (n + 5)\r
\n" ); document.write( "\n" ); document.write( "n + 6 + 5 + n + 5\r
\n" ); document.write( "\n" ); document.write( "Combine like terms:\r
\n" ); document.write( "\n" ); document.write( "n + n = 2n\r
\n" ); document.write( "\n" ); document.write( "6 + 5 + 5 = 16\r
\n" ); document.write( "\n" ); document.write( "2n + 16 = 70\r
\n" ); document.write( "\n" ); document.write( "Subtract 16 from each side of the equation.\r
\n" ); document.write( "\n" ); document.write( "2n + 16 - 16 = 70 - 16\r
\n" ); document.write( "\n" ); document.write( "Combine like terms:\r
\n" ); document.write( "\n" ); document.write( "16 - 16 = 0\r
\n" ); document.write( "\n" ); document.write( "70 - 16 = 54\r
\n" ); document.write( "\n" ); document.write( "2n = 54\r
\n" ); document.write( "\n" ); document.write( "Divide each side by 2\r
\n" ); document.write( "\n" ); document.write( "2n/2 = 54/2\r
\n" ); document.write( "\n" ); document.write( "n = 27\r
\n" ); document.write( "\n" ); document.write( "n + 6 = 27 + 6 = 33\r
\n" ); document.write( "\n" ); document.write( "Therefore:\r
\n" ); document.write( "\n" ); document.write( "A is 33 years old and\r
\n" ); document.write( "\n" ); document.write( "B is 27 years old.
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