document.write( "Question 622347: one number is eight more than a second number. three times the first is eight less than five times the second. find the numbers. \n" ); document.write( "

Algebra.Com's Answer #391313 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "let's numbers be:\r
\n" ); document.write( "\n" ); document.write( "first: $\"x\"$ \r
\n" ); document.write( "\n" ); document.write( "second: $\"y\"$ }\r
\n" ); document.write( "\n" ); document.write( "if first number is eight more than a second number, we have\r
\n" ); document.write( "\n" ); document.write( " $\"x=y%2B8\"$ ............1\r
\n" ); document.write( "\n" ); document.write( "if three times the first is eight less than five times the second, we have\r
\n" ); document.write( "\n" ); document.write( " $\"3x%2B8=5y\"$ ............2\r
\n" ); document.write( "\n" ); document.write( "now, solve the system:\r
\n" ); document.write( "\n" ); document.write( " $\"x=y%2B8\"$ ............1...substitute in 2\r
\n" ); document.write( "\n" ); document.write( " $\"3x%2B8=5y\"$ ............2
\n" ); document.write( "------------------------------\r
\n" ); document.write( "\n" ); document.write( " $\"3%28y%2B8%29%2B8=5y\"$ ............2...solve for $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3y%2B24%2B8=5y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"24%2B8=5y-3y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"32=2y\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"highlight%2816=y%29\"$ ....now find $\"x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=y%2B8\"$ ............1\r
\n" ); document.write( "\n" ); document.write( " $\"x=16%2B8\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28x=24%29\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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