document.write( "Question 622091: I need to learn this with the reinforcement of detailed instructions on how to get to these final results. Thank you.\r
\n" ); document.write( "\n" ); document.write( "The monthly value of a share of ACME Corporation, in dollars, since January 2009 are shown in the table below. The values of the table below model the behavior of a quadratic function when it is graphed.\r
\n" ); document.write( "\n" ); document.write( "Month ------ Share Value (in dollars)
\n" ); document.write( "0 ------ 55
\n" ); document.write( "3 ------ 16
\n" ); document.write( "5 ------ 0
\n" ); document.write( "7 ------ -8
\n" ); document.write( "9 ------ -8
\n" ); document.write( "11 ------ 0
\n" ); document.write( "13 ------ 16
\n" ); document.write( "15 ------ 40\r
\n" ); document.write( "\n" ); document.write( "1. Using the table above, find the quadratic equation that represents the monthly value of a share of ACME Corporation since January 2009. Use the variable x to represent the number of months after January 2009 and the variable y to represent the monthly value\r
\n" ); document.write( "\n" ); document.write( "2. Find the y-intercept. Interpret the meaning of the y-intercept in relation to the given real-life scenario\r
\n" ); document.write( "\n" ); document.write( "3. Find the x-intercepts. Interpret the meaning of the x-intercepts in relation to the given real-life scenario.\r
\n" ); document.write( "\n" ); document.write( "4. From the equation you found in problem 1, what is the concavity of the parabola? How do you know? What is the lowest or maximum monthly value of a share of ACME Corporation and when did that occur?\r
\n" ); document.write( "\n" ); document.write( "5. Using the quadratic equation you found in problem 1, predict the value of a share of ACME Corporation in October 2010?
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Algebra.Com's Answer #391300 by KMST(5328)\"\" \"About 
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If this was a real life set of data, I would first plot the points to see what shape they suggest. Next, I would use some computer software to do linear regression and find the fit of the functions that I suspect best fit the data points.
\n" ); document.write( "If I only had pencil and paper. I would hand-draw a smooth curve that fit the points, and use my knowledge of math to figure out an equation for the function that represents the data.
\n" ); document.write( "The problem says it's a quadratic function, so we need to do none of that.
\n" ); document.write( "
\n" ); document.write( "1. Three points determine a quadratic function (we may have to solve a system of equations to find coefficients), and all points would be used to verify the fit.
\n" ); document.write( "A quadratic function can be represented as
\n" ); document.write( "\"y=ax%5E2%2Bbx%2Bc\" or
\n" ); document.write( "\"y=a%28x-k%292%2Bh\" with \"x=k\" being the axis of symmetry and (k,h) being the coordinates of the vertex.
\n" ); document.write( "If y=0 for x=s and x=t, then quadratic polynomial can be factored, and the function could be represented as
\n" ); document.write( "\"y=a%28x-s%29%28x-t%29\".
\n" ); document.write( "We have that last option, and it may be the easiest way to solve the problem.
\n" ); document.write( "We have \"y=a%28x-11%29%28x-5%29\" and we just have to find a.
\n" ); document.write( "For x=0,
\n" ); document.write( "\"y=a%28-11%29%28-5%29=55a=55\" --> \"a=1\"
\n" ); document.write( "So \"y=%28x-11%29%28x-5%29\" or \"y=x%5E2-16x%2B55\" could be the answer.
\n" ); document.write( "We may want to express it in another way,
\n" ); document.write( "completing the square for \"x%5E2-16x\" like this
\n" ); document.write( "\"y-55=x%5E2-16x\" --> \"y-55%2B64=x%5E2-16x%2B64\" --> \"y%2B9=%28x-8%29%5E2\" --> \"highlight%28y=%28x-8%29%5E2-9%29\"
\n" ); document.write( "The second option works well too, because the data suggests that the axis of symmetry is x=8, so we expect the equation to be
\n" ); document.write( "\"y=a%28x-8%29%5E2%2Bh\".
\n" ); document.write( "With the (x,y) coordinates of a couple of points we could set up a system of equations and find a and h.
\n" ); document.write( "For x=9, \"y=a%289-8%29%5E2%2Bh=a%2Bh=-8\" and
\n" ); document.write( "For x=11, \"y=a%2811-8%29%5E2%2Bh=a%2A3%5E2%2Bh=9a%2Bh=0\"
\n" ); document.write( "give us \"system%28a%2Bh=-8%2C9a%2Bh=0%29\" which gives us a=8 and h=-9,
\n" ); document.write( "so we get \"highlight%28y=%28x-8%29%5E2-9%29\"
\n" ); document.write( "2. The y-intercept is the y value when x=0. It is y=55. It is the share value for x=0, month zero, January 2009.
\n" ); document.write( "3. The x-intercepts are the x values where y=0, x=7 and x=9. The share value was zero at months 7 and 9 after January 2009. That happened on August and October 2009.
\n" ); document.write( "4. The equation has a negative coefficient a, so the parabola opens up. It's concave upwards, and the graph looks like a smile. The lowest point is the vertex (8,-9). It represents the lowest share value (-0), which occurred at month 8, in September 2009. The value of a share of ACME Corporation was -$9 then.
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