document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=622305>Question 622305</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 38 inches, and the area is 90 square inches. Find the dimensions of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #391286 by </B><A HREF=/tutors/aboutme.mpl?userid=Emsley><B>Emsley(35)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Emsley><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=391286\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let length =x and breadth=y<BR>\n" );
document.write( "Then xy=90 and 2x+2y=38 so x+y=19<BR>\n" );
document.write( "x=90/y Sub in x+y=19 and get 90/y+y=19<BR>\n" );
document.write( "Multiply both sides by y  90+y^2=19y   y^2-19y+90=0<BR>\n" );
document.write( "Factorising (y-10)(y-9)=0 so y=10 or 9<BR>\n" );
document.write( "But y was the breadth so y=9 and x=10<BR>\n" );
document.write( "That is length =10 and breadth=9<BR>\n" );
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