document.write( "Question 622288: The formula for the volume of a sphere is V=4/3(pi)r^3. Find the radius to the nearest hundredth of a sphere with each volume. V= 20ft^3. Could you please explain how you got the answer so I know how to do the other problems? Thank You!! \n" ); document.write( "
Algebra.Com's Answer #391273 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Take out your calculator\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply the volume by \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide the result by \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Take the cube root of the result.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Round appropriately. You might want to ask your instructor why, since the Volume was given to the nearest cubic foot, you were asked to round to the nearest hundredth of a foot. Totally inappropriate. The result of a calculation involving measurements should never be expressed more precisely than the least precise given measurement. If the instructor wanted the answer to the nearest 1/100 foot, s/he should have expressed the Volume as 20.00 ft^3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |