document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=622283>Question 622283</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve (y-6)(y+1)=-12? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #391268 by </B><A HREF=/tutors/aboutme.mpl?userid=matineesuxxx><B>matineesuxxx(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=matineesuxxx><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=391268\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use Foil to expand everything on the left side of the bracket, then add 12 to both sides of the equation and solve. \r<BR>\n" );
document.write( "\n" );
document.write( "HINT: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E2-5y%2B6=0 ALIGN=MIDDLE  ALT=\"y%5E2-5y%2B6=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >, what do -2 and -3 have to do with this equation? </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );