document.write( "Question 622266: Two people leave their homes at 11:30 am and between the two of them, they drive a total of 37.5 miles. one drives an average of 15mph faster then the other . they meet at noon find the average driving speed for each?\r
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document.write( "d=rt
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document.write( "d=37.5
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document.write( "t=30 min
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document.write( "let x =rate
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document.write( "x(15) + x * 30 min = 37.5
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document.write( "16x * 30 min = 37.5
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document.write( "I don't know if I am on the right track but I don't know where to go from here
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document.write( "Please help with a formula \n" );
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Algebra.Com's Answer #391252 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( " \n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------- \n" ); document.write( "Slower driver's equation: \n" ); document.write( "(1) \n" ); document.write( "Faster driver's equation: \n" ); document.write( "(2) \n" ); document.write( "--------------------------- \n" ); document.write( "Substitute (1) into (2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "The speed of the slower driver is 30 mi/hr \n" ); document.write( "The speed of the faster driver is 45 mi/hr \n" ); document.write( "check: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "and \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "OK \n" ); document.write( " |