document.write( "Question 622057: what is the three-digit number which satisfies the following conditon? The tens digit is greater than the ones digit, the sum of the digits is 9, and if the digits are reversed and the resulting three-digit number is subtracted fron the original number, the difference is 198. \n" ); document.write( "
Algebra.Com's Answer #391237 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The three digits are a, b, c \n" ); document.write( "then \n" ); document.write( "100a + 10b + c = \"the number\" \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "\"The tens digit is greater than the ones digit,\" \n" ); document.write( "b > c \n" ); document.write( ": \n" ); document.write( "\"the sum of the digits is 9,\" \n" ); document.write( "a + b + c = 9 \n" ); document.write( ": \n" ); document.write( "\" and if the digits are reversed and the resulting three-digit number is subtracted from the original number, the difference is 198.\" \n" ); document.write( "100a + 10b + c -(100c + 10b + a) = 198 \n" ); document.write( "Removing the brackets changes the signs \n" ); document.write( "100a + 10b + c - 100c - 10b - a = 198 \n" ); document.write( "Combine like terms \n" ); document.write( "100a - a + 10b - 10b + c - 100c = 198 \n" ); document.write( "99a - 99c = 198 \n" ); document.write( "simplify, divide by 99 \n" ); document.write( "a - b = 2 \n" ); document.write( "a = b+2 \n" ); document.write( ": \n" ); document.write( "Replace a with (b+2) in the sum equation \n" ); document.write( "(b+2) + b + c = 9 \n" ); document.write( "2b + c = 9-2 \n" ); document.write( "2b + c = 7 \n" ); document.write( "From this assume b=3, then c=1 and a=5 \n" ); document.write( "531 is the number \n" ); document.write( " \n" ); document.write( " |