document.write( "Question 622162: An experiment started with 600 bacteria. They double in number every hour. Find the number of bacteria after 4 hours. \n" ); document.write( "
Algebra.Com's Answer #391190 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! An experiment started with 600 bacteria. They double in number every hour. Find the number of bacteria after 4 hours. \n" ); document.write( "1200 = 600e^(1r) \n" ); document.write( "1200/600 = e^(r) \n" ); document.write( "2 = e^(r) \n" ); document.write( "ln(2) = r \n" ); document.write( ". \n" ); document.write( "general equation: \n" ); document.write( "A = 600e^(tln(2)) \n" ); document.write( "for 4 hours: \n" ); document.write( "A = 600e^(4ln(2)) \n" ); document.write( "A = 600e^(2.77259) \n" ); document.write( "A = 9600 bateria\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |