document.write( "Question 622162: An experiment started with 600 bacteria. They double in number every hour. Find the number of bacteria after 4 hours. \n" ); document.write( "
Algebra.Com's Answer #391190 by nerdybill(7384)\"\" \"About 
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An experiment started with 600 bacteria. They double in number every hour. Find the number of bacteria after 4 hours.
\n" ); document.write( "1200 = 600e^(1r)
\n" ); document.write( "1200/600 = e^(r)
\n" ); document.write( "2 = e^(r)
\n" ); document.write( "ln(2) = r
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\n" ); document.write( "general equation:
\n" ); document.write( "A = 600e^(tln(2))
\n" ); document.write( "for 4 hours:
\n" ); document.write( "A = 600e^(4ln(2))
\n" ); document.write( "A = 600e^(2.77259)
\n" ); document.write( "A = 9600 bateria\r
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